# How do you find the domain of the function: f(x) = sqrt(4-3x)?

##### 1 Answer
Apr 19, 2015

$x \in$ R, $x \le \frac{4}{3}$

The domain of the function is a field of real numbers x, in which f(x) would be real.

For this to be happen, $4 - 3 x \ge 0$

That is $4 \ge 3 x$, Or $\frac{4}{3} \ge x$.

$x \in$ R, $x \le \frac{4}{3}$