# How do you find the domain of the function F(x) = (x^2+3x+4)/(x^2+1)^(1/2)?

May 16, 2018

$x \in \mathbb{R}$

#### Explanation:

$\text{the denominator of "f(x)" cannot be zero as this}$
$\text{would make "f(x)" undefined}$

$\text{note that "sqrt(x^2+1)>0" for all real values of x}$

$\text{thus there are no values of x which make the denominator}$
$\text{equal to zero}$

$\text{domain is } x \in \mathbb{R}$
graph{(x^2+3x+4)/(sqrt(x^2+1)) [-10, 10, -5, 5]}