# How do you find the equation of a parabola when given two points (2,10) and (4,10)?

##### 1 Answer

There's not enough information here to uniquely determine the parabola, but enough to find:

#### Explanation:

Since the

So the equation of the parabola takes the form:

If we substitute

So

The constant

Here are the parabolas for

graph{(y-x^2+6x-18)(y+x^2-6x-2)(y-2x^2+12x-26)(y+2x^2-12x+6)=0 [-2.585, 7.415, 7.22, 12.22]}