# How do you find the exact solution to arcsin (-1/ sqt 2)?

Find $\arcsin \left(- \frac{1}{\sqrt{2}}\right)$
$\sin x = - \frac{1}{\sqrt{2}} = - \frac{\sqrt{2}}{2}$ --> arc $x = \frac{5 \pi}{4}$ and $x = \frac{7 \pi}{4}$