# How do you find the exact value of tan^-1 0?

Sep 28, 2017

0

#### Explanation:

Remember that $\tan \left(\theta\right) = \sin \frac{\theta}{\cos} \left(\theta\right)$

You're looking for some angle $\theta$ for which $\sin \frac{\theta}{\cos} \left(\theta\right) = 0$

...this occurs whenever $\sin \left(\theta\right) = 0$.

Which happens when $\theta = 0 , \pi , 2 \pi ,$ (etc.)

For the inverse trig functions, you use only the first angle in this list.

So therefore, you can deduce that ${\tan}^{-} 1 \left(0\right) = 0$

GOOD LUCK!