How do you find the first 4 terms of a geometric sequence with a first term of 2 and a common ratio of 4?

1 Answer
Mar 22, 2018

#"First four terms are " 2, 8, 32, 128#

Explanation:

Given #"First Term " a = 2, "Common ratio " r = 4#

https://www.onlinemathlearning.com/geometric-sequence.html

#n^(th) term " " a_n = a * r^ (n - 1)#

Hence, #a_2 = a * r^(2 - 1) = a r = 2 * 4 = 8#

#a_3 = a * r^(3 - 1) = a r^2 = 2 * 4^2 = 32#

#a_4 = a * r^(4 - 1) = a r^3 = 2 * 4^3 = 128#

#a_5 = a r^4 = 2 * 4^4 = 512#