# How do you find the first, fourth, and eighth terms of the sequence A(n) = -2*5^(n-1)?

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#### Explanation

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#### Explanation:

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Jul 26, 2017

See a solution process below:

#### Explanation:

To find any term in the sequence, substitute the number of the term for $n$ and calculate the result:

First Term

$A \left(\textcolor{red}{n}\right) = - 2 \cdot {5}^{\textcolor{red}{n} - 1}$ becomes:

$A \left(\textcolor{red}{1}\right) = - 2 \cdot {5}^{\textcolor{red}{1} - 1} = - 2 \cdot {5}^{0} = - 2 \cdot 1 = - 2$

Fourth Term

$A \left(\textcolor{red}{n}\right) = - 2 \cdot {5}^{\textcolor{red}{n} - 1}$ becomes:

$A \left(\textcolor{red}{4}\right) = - 2 \cdot {5}^{\textcolor{red}{4} - 1} = - 2 \cdot {5}^{3} = - 2 \cdot 125 = - 250$

Eight Term

$A \left(\textcolor{red}{n}\right) = - 2 \cdot {5}^{\textcolor{red}{n} - 1}$ becomes:

$A \left(\textcolor{red}{8}\right) = - 2 \cdot {5}^{\textcolor{red}{8} - 1} = - 2 \cdot {5}^{7} = - 2 \cdot 78125 =$

$156 , 250$

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