# How do you find the greatest common factor of 60y, 56x^2?

4

#### Explanation:

To find the GCF, let's see what these two terms are made of:

$60 y = 2 \times 30 y = 2 \times 2 \times 15 y = 2 \times 2 \times 3 \times 5 \times y$

$56 {x}^{2} = 2 \times 28 {x}^{2} = 2 \times 2 \times 14 {x}^{2} = 2 \times 2 \times 2 \times 7 \times {x}^{2}$

So what is the biggest number we can make that is within both of the terms we're looking at?

There are two 2s that both terms have - and nothing else in common. So the GCF is $2 \times 2 = 4$

$4 \times 15 y = 60 y$
$4 \times 14 {x}^{2} = 56 {x}^{2}$