How do you find the horizontal asymptote for #4/(1+e^(1-x)) #?

1 Answer

Answer:

#y=4# and #y=0# are horizontal asymptotes

Explanation:

Let #y=4/(1+e^(1-x))#

Try to imagine the value of #y# if #x# is made to increase up to #+oo#

As #x# approaches the value #+oo#
#y# approaches #4#

Try to imagine the value of #y# if #x# is made to decrease down to #-oo#

As #x# approaches the value #-oo#
#y# approaches #0#

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