Question

How do you find the horizontal asymptote for `h(x)=5^(x-2)`?

Answer 1

Horizontal asymptote: `h(x)=0`

Explanation:

As `xrarr-oo`
`color(white)("XXX")lim_(xrarr-oo)5^(x-2)`

`color(white)("XXX")=lim_(xrarr-oo) 1/(5^abs(x-2))`

`color(white)("XXX")=0`