How do you find the important points to graph #y = 2^x + 2#?

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Answer 1 · 2018-02-14T18:34:08

You can use the points #(0,3),(1,4),(2,6)#. Also use the asymptote #y=2#.

In an exponential graph, one of the most important points is the y-intercept. You can find this by plugging in #0# for #x#:

#y=2^0+2#

Anything to the zeroth power is #1#.

#y=1+2#

#y-3#

The y-int is #(0,3)#.

You can also plug in #1 and 2# in #x# to find some other points.

#y=2^1+2=4#

#y=2^2+2=6#

You can use the points #(0,3),(1,4),(2,6)#.

Also consider the asymptote, #y=2#. Check out this graph for reference:

graph{2^x+2 [-9.58, 10.42, -0.08, 9.92]}