# How do you find the indefinite integral of int -3 dx?

Sep 4, 2016

Knowing that $\int {x}^{n} \mathrm{dx} = {x}^{n + 1} / \left(n + 1\right) , n \ne - 1$,

$\int - 3 \mathrm{dx} = - 3 \int {x}^{0} \mathrm{dx} = - 3 \cdot {x}^{0 + 1} / \left(0 + 1\right) = - 3 x + C$.

Sep 4, 2016

$- \frac{3}{2} {x}^{2} + c$

#### Explanation:

Use the $\textcolor{b l u e}{\text{power rule for integration}}$

$\textcolor{\mathmr{and} a n \ge}{\text{Reminder }} \textcolor{red}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{\int \left(a {x}^{n}\right) \mathrm{dx} = \frac{a}{n + 1} {x}^{n + 1}} \textcolor{w h i t e}{\frac{a}{a}} |}}}$

$\Rightarrow \int \left(- 3 x\right) \mathrm{dx} = \frac{- 3}{2} {x}^{2} + c = - \frac{3}{2} {x}^{2} + c$

c- constant of integration.