# How do you find the indefinite integral of ∫ x^2 - 2 dx / x^3 - 4x ?

##### 2 Answers

Apr 15, 2018

#### Explanation:

We want to solve

#I=int(x^2-2)/(x^3-4x)dx#

Multiply the DEN and NUM by

#I=int(x^3-2x)/(x^4-4x^2)dx#

Now we can make i nice substitution

#I=1/4int1/udu#

#color(white)(I)=1/4ln(u)+C#

#color(white)(I)=1/4ln(x^4-4x^2)+C#

Apr 16, 2018

I have solved this way, applying partial fractions decomposition: