How do you find the inner product and state whether the vectors are perpendicular given #<-3,2>*<4,6>#?

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Answer 1 · 2017-04-11T09:52:40

#0#

and perpendicular

For two vectors

# < a_1,b_1> "< a_2,b_2>#

the inner product is calculated by:

# < a_1,b_1> . < a_2,b_2> =a_1a_2+b_1b_2#

# < -3,2> . < 4,6> = -3xx4+2xx6#

#=-12+12=0#

since the inner product is zero the vectors are perpendicular