How do you find the instantaneous slope of #y=4-x^2# at x=1? Calculus Derivatives Instantaneous Rate of Change at a Point 1 Answer Ratnaker Mehta Jul 20, 2016 The reqd. slope #=[dy/dx]_(x=1)# #=[-2x]_(x=1)=-2#. Explanation: The reqd. slope #=[dy/dx]_(x=1)# #=[-2x]_(x=1)=-2#. Answer link Related questions How do you find the instantaneous rate of change of a function at a point? What is Instantaneous Rate of Change at a Point? How do you estimate instantaneous rate of change at a point? How do you find the instantaneous rate of change of #f (x)= x ^2 +2 x ^4# at #x=1#? How do you find the instantaneous rate of change of #f(t)=(2t^3-3t+4)# when #t=2#? How do you find the instantaneous rate of change of #w# with respect to #z# for #w=1/z+z/2#? Can instantaneous rate of change be zero? Can instantaneous rate of change be negative? How do you find the instantaneous rate of change at a point on a graph? How does instantaneous rate of change differ from average rate of change? See all questions in Instantaneous Rate of Change at a Point Impact of this question 1294 views around the world You can reuse this answer Creative Commons License