# How do you find the integral of 1/tan(x) dx?

$\ln | \sin x | + C$
$\int \frac{1}{\tan} x \mathrm{dx} = \int \frac{1}{\sin \frac{x}{\cos} x} \mathrm{dx} = \int \cos \frac{x}{\sin} x \mathrm{dx} = \int \frac{d \left(\sin x\right)}{\sin} x = \ln | \sin x | + C$