# How do you find the intercept and vertex of #y= -x^2 + 9#?

##### 1 Answer

Jul 14, 2016

Vertex is

Its y-intercept is

#### Explanation:

Given -

#y=-x^2+9#

It has no

#y=-x^2+0x+9#

Then it is in the form

#x=(-b)/(2a)=0/(2xx(-1))=0 #

At

Vertex is

Its y-intercept is