How do you find the intercepts for #y=2x^2-5x+2#?
Ok so I know the picture is a little hard to read as this was done on my doodle pad.
However, here is a written expression.
First, divide a and c which would be 2 and 2.
Then, find two numbers that multiply 4 and add -5 which would be -1 and -4.
Next, split the middle with 2x^2-4x-1x+2.
This part's a little tricky, but hang in there :)
Ok, so factor out a 2x from the 2x^2 and a -1 from -1x+2, both answers should be (x-2)
Now this a little hard to explain, but since you used both 2x and -1 to divide 2x^2-4x-1x+2, write (2x-1).
Now your final answers should be (2x-1) (x-2)
Going further to find your x-intercepts, set each equation to zero.
2x-1=0 is x=1/2
x-2=0 is x=2
Your x intercepts are 1/2 and 2.
Hope this helped! :)