How do you find the intercepts of #3x-6y=24#?

1 Answer
EZ as pi
Nov 30, 2016

x=intercept is #(8,0)# and y-intercept is #(0,-24)#

Explanation:

All along the #x# axis, # y=0# and all along the #y# axis, #x=0#

TO find the #x#-intercept, make #y=0#

#3x-6(0) = 24#
#3x = 24#
#x = 8" "rarr# x=intercept is #(8,0)#

TO find the #y# intercept, make #x# =0

#3(0) -y = 24#
#-y = 24#
#y = -24" "rarr# y-intercept is #(0,-24)#

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