# How do you find the inverse of f(x) =x^3-2?

Oct 14, 2015

$\sqrt[3]{x + 2}$

#### Explanation:

Equate f(x) to some variable, say y. f(x)=y.

So,
${x}^{3} - 2 = y$
${x}^{3} = y + 2$
x=$\sqrt[3]{y + 2}$

Now swap in $x$ for $y$. And f(x) inverse is= $\sqrt[3]{x + 2}$

(Sorry if the formatting is wrong, I'm pretty new here but as the answer reads, f inverse of x is equal to cube root of x plus 2)