# How do you find the inverse of the function y=log(x-2)?

Nov 19, 2016

${f}^{-} 1 \left(x\right) = {10}^{x} + 2$

#### Explanation:

Switch the $x$ and $y$ values and solve for $y$.

$y = \log \left(x - 2\right)$

$x = \log \left(y - 2\right)$

${10}^{x} = y - 2$

$y = {10}^{x} + 2$

Hopefully this helps!