# How do you find the LCD for 2x(x-1) , x^2- 1 , 4?

Oct 7, 2017

$L C D = 4 x \left({x}^{2} - 1\right)$

#### Explanation:

The given terms are
$2 x \left(x - 1\right) , \left({x}^{2} - 1\right) , 4$
Factors of each term :
$2 x \left(x - 1\right) = 2 \cdot x \cdot \left(x - 1\right)$
$\left({x}^{2} - 1\right) = \left(x + 1\right) \left(x - 1\right)$
$4$
$L C D = 4 \cdot \left(x + 1\right) \left(x - 1\right) \cdot x = 4 x \left({x}^{2} - 1\right)$