# How do you find the limit #lim_(x->0)sin(x)/x# ?

##### 1 Answer

Aug 18, 2014

We will use l'Hôpital's Rule.

l'Hôpital's rule states:

#lim_(x->a) f(x)/g(x) = lim_(x->a) (f'(x))/(g'(x))#

In this example,

Thus,

#lim_(x->0) (sinx)/x = lim_(x->0) (cosx)/(1)#

Quite clearly, this limit evaluates to