Question

How do you find the limit of `1/e^x` as x approaches `oo`?

Answer 1

`lim_(xrarr+oo)1/e^x=1/e^(+oo)=1/oo=0`

Explanation:

Show below the sketch of `y=e^x`
graph{e^x [-7.024, 7.024, -3.51, 3.513]}

`lim_(xrarr+oo)1/e^x=1/e^(+oo)=1/oo=0`

Note that:

`c/(+-oo)=0` where c any constant.