# How do you find the limit of (1)/(x-2)  as x approaches 2^+?

Jun 29, 2016

${\lim}_{x \rightarrow {2}^{+}} \frac{1}{x - 2} = + \infty$

#### Explanation:

As $x \rightarrow {s}^{+}$
$\textcolor{w h i t e}{\text{XXX}} x - 2 \rightarrow 0$ but remains positive.

Therefore
$\textcolor{w h i t e}{\text{XXX}} \frac{1}{x - 2}$ remains positive.

and since $\left(x - 2\right) \rightarrow 0$
$\textcolor{w h i t e}{\text{XXX}} \frac{1}{x - 2} \rightarrow + \infty$