How do you find the limit of (x^2+x-12)/(x-3) as x->1? Calculus Limits Determining Limits Algebraically 1 Answer Noah G Oct 15, 2016 Since 1 doesn't render the denominator 0, you can substitute directly into the function. lim_(x -> 1) (x^2 + x - 12)/(x - 3) = (1^2 + 1 - 12)/(1 - 3) = (-10)/(-2) = 5 Hopefully this helps! Answer link Related questions How do you find the limit lim_(x->5)(x^2-6x+5)/(x^2-25) ? How do you find the limit lim_(x->3^+)|3-x|/(x^2-2x-3) ? How do you find the limit lim_(x->4)(x^3-64)/(x^2-8x+16) ? How do you find the limit lim_(x->2)(x^2+x-6)/(x-2) ? How do you find the limit lim_(x->-4)(x^2+5x+4)/(x^2+3x-4) ? How do you find the limit lim_(t->-3)(t^2-9)/(2t^2+7t+3) ? How do you find the limit lim_(h->0)((4+h)^2-16)/h ? How do you find the limit lim_(h->0)((2+h)^3-8)/h ? How do you find the limit lim_(x->9)(9-x)/(3-sqrt(x)) ? How do you find the limit lim_(h->0)(sqrt(1+h)-1)/h ? See all questions in Determining Limits Algebraically Impact of this question 1137 views around the world You can reuse this answer Creative Commons License