# How do you find the limit of  (x^3 - 5x^2 + 7x - 3)/(x^3 - x^2 - 5x - 3) as x approaches 3?

$\frac{1}{4}$
Divide both polynomia by $x - 3$, then
${\lim}_{x \to 3} \frac{\left(x - 3\right) {\left(x - 1\right)}^{2}}{\left(x - 3\right) {\left(x + 1\right)}^{2}} = {\left(3 - 1\right)}^{2} / {\left(3 + 1\right)}^{2} = \frac{1}{4}$