How do you find the limits?

Indeterminate Forms
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1 Answer
Oct 23, 2017

#e#

Explanation:

There exist a calculus book limit which is

#lim_(y->0)(1+y)^(1/y) = e#

In #lim_(x->0)(1+x+x^2)^(1/x)# when #x# is very small #x^2 << << x# so the contribution of #x^2# is discarded regarding #x# so

#lim_(x->0)(1+x+x^2)^(1/x) = lim_(x->0)(1+x)^(1/x) = e#