How do you find the magnitude <-6,-11>? Precalculus Vectors in the Plane Vector Operations 1 Answer Ratnaker Mehta Jul 13, 2016 #sqrt157~=12.53# Explanation: Magnitude of a vector #vecx=(x_1,x_2)# is denoted by #||vecx||# & is defined by, #||vecx||=sqrt(x_1^2+x_2^2).# Hence, magnitude of vector #<-6,-11># is #sqrt{(-6)^2+(-11)^2}=sqrt157~=12.53# Answer link Related questions Question #b4ef9 What is meant by a component of a vector? How do I find the vertical component of a vector? How do i find the horizontal component of a vector? Is vector addition commutative? What happens when I multiply a vector by itself? What is the definition of vector addition? How do I do vector subtraction? What is a velocity vector? How can the law of cosines be used to find the magnitude of a resultant? See all questions in Vector Operations Impact of this question 1720 views around the world You can reuse this answer Creative Commons License