Question

How do you find the magnitude and direction angle of the vector `v=8(cos135^circi+sin135^circj)`?

Answer 1

Standard form:
magnitude ( cos ( direction angle ) `veci` + sin ( direction angle ) `vecj )`. Answer: 8, and `135^o in Q_2`.

Explanation:

Graph for like-parallel `vec v`, from O:
graph{(x^2+y^2-64)(y+0.707x)=0[-5.7 0 0 2.8]}