How do you find the magnitude of <2.5,6> and write it as a sum of the unit vectors? Precalculus Vectors in the Plane Vector Operations 1 Answer Ratnaker Mehta Sep 3, 2017 #:. <2.5,6> = 2.5hati+6hatj.# #||<2.5,6>||=sqrt{(2.5)^2+6^2}=sqrt(6.25+36)=sqrt(42.25)=6.5.# Explanation: #<2.5,6> = <2.5,0> + <0,6>,# # =2.5<1,0> + 6<0,1>,# #:. <2.5,6> = 2.5hati+6hatj.# #||<2.5,6>||=sqrt{(2.5)^2+6^2}=sqrt(6.25+36)=sqrt(42.25)=6.5.# Answer link Related questions Question #b4ef9 What is meant by a component of a vector? How do I find the vertical component of a vector? How do i find the horizontal component of a vector? Is vector addition commutative? What happens when I multiply a vector by itself? What is the definition of vector addition? How do I do vector subtraction? What is a velocity vector? How can the law of cosines be used to find the magnitude of a resultant? See all questions in Vector Operations Impact of this question 1301 views around the world You can reuse this answer Creative Commons License