How do you find the magnitude of <2.5,6> and write it as a sum of the unit vectors?

1 Answer
Ratnaker Mehta
Sep 3, 2017

#:. <2.5,6> = 2.5hati+6hatj.#

#||<2.5,6>||=sqrt{(2.5)^2+6^2}=sqrt(6.25+36)=sqrt(42.25)=6.5.#

Explanation:

#<2.5,6> = <2.5,0> + <0,6>,#

# =2.5<1,0> + 6<0,1>,#

#:. <2.5,6> = 2.5hati+6hatj.#

#||<2.5,6>||=sqrt{(2.5)^2+6^2}=sqrt(6.25+36)=sqrt(42.25)=6.5.#

Related questions
See all questions in Vector Operations
Impact of this question
1320 views around the world
You can reuse this answer
Creative Commons License