# How do you find the maximum and minimum of y=-2(x+1)^2+6?

Mar 17, 2017

Find the vertex.

#### Explanation:

Finding the maximum or minimum for a quadratic equation like this one is code for finding the vertex.

If $y = a {\left(x - h\right)}^{2} + k$ then vertex is $\left(h , k\right)$

In this case is $- h = 1$ and $k = 6$
So vertex is $\left(- 1 , 6\right)$

Also, whenever a is negative in this format of equation that means you have a downward-opening parabola. Therefore the vertex is a maximum. So the maximum occurs at $\left(- 1 , 6\right)$. There is no minimum because the parabola continues down forever.