# How do you find the midpoint of ( 1/3,-4) and (-2/3,6)?

Jul 28, 2018

The midpoint is at $\left(- \frac{1}{6} , 1\right)$.

#### Explanation:

The midpoint formula is $\left(\frac{{x}_{1} + {x}_{2}}{2} , \frac{{y}_{1} + {y}_{2}}{2}\right)$.

We have two points, so let's plug them into the formula and simplify:
$\left(\frac{\frac{1}{3} + \left(- \frac{2}{3}\right)}{2} , \frac{- 4 + 6}{2}\right)$

$= \left(\frac{- \frac{1}{3}}{2} , \frac{2}{2}\right)$

$= \left(- \frac{1}{6} , \frac{2}{2}\right)$

$= \left(- \frac{1}{6} , 1\right)$

Therefore, the midpoint is at $\left(- \frac{1}{6} , 1\right)$.

Hope this helps!