# How do you find the midpoint of (2,8) and (4,6)?

Feb 29, 2016

The midpoint is $\left(3 , 7\right)$.

#### Explanation:

The midpoint formula is: $\left({x}_{m} , {y}_{m}\right) = \left(\frac{{x}_{1} + {x}_{2}}{2} , \frac{{y}_{1} + {y}_{2}}{2}\right)$

We have, ${x}_{1} = 2 , {y}_{1} = 8 , {x}_{2} = 4 , {y}_{2} = 6$

substituting the values,

$\frac{2 + 4}{2} \mathmr{and} \frac{8 + 6}{2} = \left(3 , 7\right)$

Another way of looking at the "midpoint formula" is just as taking the average of the values for $x$ and the average of the values for $y$.

Halfway between $x = 2$ and $x = 4$ is $x = 3$, and halfway between $y = 8$ and $y = 6$ is at $y = 7$, so the midpoint is $\left(3 , 7\right)$.