# How do you find the midpoint of A(-1,3) and M(-3,5)?

Jun 13, 2018

$\left(- 2 , 4\right)$

#### Explanation:

$\text{given the endpoints of a segment, say}$

$\left({x}_{1} , {y}_{1}\right) \text{ and } \left({x}_{2} , {y}_{2}\right)$

$\text{then the coordinates of the midpoint are the average of}$
$\text{the coordinates of the endpoints}$

$\left[\frac{1}{2} \left({x}_{1} + {x}_{2}\right) , \frac{1}{2} \left({y}_{1} + {y}_{2}\right)\right]$

$\text{here "(x_1,y_1)=(-1,3)" and } \left({x}_{2} , {y}_{2}\right) = \left(- 3 , 5\right)$

$\text{midpoint } = \left[\frac{1}{2} \left(- 1 - 3\right) , \frac{1}{2} \left(3 + 5\right)\right]$

$\textcolor{w h i t e}{\times \times \times x} = \left(- 2 , 4\right)$