How do you find the midpoint of the segment with the endpoints #(3,- 6)# and #( 0,- 3)#?

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Answer 1 · 2018-03-27T08:33:44

#M(3/2, -9/2)#

the midpoint of a segment is the average values of the endpoint coordinates

ie midpoint of #(x_1,y_1),(x_2,y_2)#

#M((x_1+x_2)/2,(y_1+y_2)/2)#

we ahve

#(3,-6),(0,-3)#

#:. M((3+0)/2,(-6+ -3)/2)#

#M(3/2, -9/2)#

Answer 2 · 2018-03-27T08:35:37

#(3/2,-9/2)#

To find the coordinates of the midpoint.

If the end points be:

#(x_1,y_1)# and #(x_2,y_2)#

Then the coordinates of the midpoint are:

#((x_1+x_2)/2,(y_1+y_2)/2)#

#:.#

#((3+0)/2,((-6)+(-3))/2)#

#(3/2,-9/2)#