How do you find the numerical value of one trigonometric function of x if cot x/csc x = 0.6?

2 Answers
Feb 19, 2018

#cos(x)=0.6#

Explanation:

From the basic definitions:
#color(white)("XXX")cot(x)=(cos(x))/(sin(x))#

#color(white)("XXX")csc(x)=1/(sin(x))#

So #(cot(x))/(csc(x))= (((cos(x))/(sin(x))))/((1/(sin(x))))=cos(x)#

And, since we are told #(cot(x))/(csc(x))=0.6#

therefore, #cos(x)=0.6#

Feb 19, 2018

#cosx=0.6#

Explanation:

.

#cotx/cscx=0.6#

#cotx/cscx=(cosx/sinx)/(1/sinx)=cosx/cancelcolor(red)sinx*cancelcolor(red)sinx/1=cosx=0.6#