Question

How do you find the perimeter of a rectangle that has a width of 74 inches and has a length that is twice its width?

Answer 1

`444`

Explanation:

The perimeter `2p` is given by

`2p = w+w+l+l = 2w+2l = 2(w+l)`

But we know that the length is twice the width, so we can substitute `l = 2w`:

`2(w+l) = 2(w+2w) = 2(3w)=6w=6*74 = 444`