# How do you find the perimeter of an isosceles triangle whose base is 16 dm and whose height is 15 dm?

Draw the triangle first, The height is 15 and base is 16. Cut the triangle in half and you will end up with two triangles with a height of 15 and base of 8. Use the Pythagoras theorem and get the slant height. ${a}^{2} = {b}^{2} + {c}^{2}$ By using this equation you will find the slant height
${x}^{2} = {15}^{2} + {8}^{2}$ simplify this and you will get 17 dm. perimeter=17+16+17=50dm