How do you find the period and amplitude of #y=-3sin(x/3)#?

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Answer 1 · 2018-06-20T04:04:57

As below.

#y = A sin (Bx - C) + D#

#y = -3 sin (x/3)#

#A = -3, B = 1/3), C = D = 0#

#"Amplitude " = |A| = |-3| = 3#

#"Period " = (2pi) / |B| = (2pi) / (1/3) = 6pi#

#"Phase Shift " = -C / B = 0#

#"Vertical Shift " = D = 0#

graph{-3 sin (x/3) [-10, 10, -5, 5]}