Question

How do you find the period of `H = 10 + 4 sin (pi/6)(t)`?

Answer 1

12.

Explanation:

The period of sin kt is `(2pi)/k` and so is the period of a + b sin kt.

Here, `k = pi/6, (2pi)/k=12`.

Check:
`H(t+12) =10+4 sin ((pi/6)(t+12))`
`=10+4sin((pi/6)t+2pi)`
`=10+4sin (pi/6)t`
`=H(t)`