# How do you find the period of #y = (1/2) sin ((x/3)-π)#?

##### 1 Answer

Jun 7, 2016

#### Explanation:

A sine function appears in the form

#y=asin(bx+c)+d#

Where the period of the function can be found by taking

Here, we can slightly rewrite the given function to make the value of

#y=1/2sin(1/3x-pi)#

Thus,

So, the period of the function is

Note that dividing by