# How do you find the period of y=3tan[2x-(pi/6)]?

Refer to explanation

#### Explanation:

The graph of the function is

graph{3*tan(2x-pi/6) [-10, 10, -5, 5]}

The period for a function with formula
$y = a \cdot \tan \left(b x + c\right)$ is $T = \frac{\pi}{b}$ hence in our
case $T = \frac{\pi}{2}$