Question

How do you find the period of `y=sin(-1/3x)`?

Answer 1

Period of`y = sin ((-x)/3)`

Explanation:

The period of `sin ((-x)/3)` is ( 6pi.), because:

`sin (-x/3) = - sin (x/3 + 2pi) = - sin [1/3(x + 6pi)]`

Therefor, the period of `sin (-x/3)` is `6pi.`