How do you find the period, phase and vertical shift of #y=cottheta+6#?

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Answer 1 · 2018-03-01T11:23:40

Amplitude # = a = 1#, Period # pi / b = pi#, Phase shift # c / b = 0#,

vertical shift # = d = 6#

Standard form of equation is #y = a cot (btheta - c) + d#

Given #y = cot theta + 6#

#a = 1, b = 1, c = 0, d = 6#

Amplitude #= a = 1#

Period # = pi / |b| = pi#

Vertical shift # = d = 6#

graph{cot x + 6 [-10, 10, -5, 5]}