How do you find the pH of a solution whose #[H^+] = 3.44 times 10^-12?#?

2 Answers
May 27, 2017

Answer:

Well, by definition #pH=-log_10[H_3O^+].............#

Explanation:

So here #pH=-log_10(3.44xx10^-12).............#

#=-(-11.46)=11.5#

For a few more details see this old answer.

May 27, 2017

Answer:

pH = 11.5

Explanation:

My own work (Mert METÄ°N)