How do you find the point of intersection for 3x-y= -4 and 3x-y=0?

Jul 12, 2015

These equations are of parallel lines, with no intersection.

If you try to satisfy both equations with the same values of $x$ and $y$ then you find:

$- 4 = 3 x - y = 0$

Explanation:

Both equations have the same coefficients of $x$ and $y$ but different constant terms. They represent parallel lines:

graph{(3x-y+4)(3x-y) = 0 [-10, 10, -5, 5]}