# How do you find the point (x,y) on the unit circle that corresponds to the real number t=pi/3?

Jul 19, 2017

$\left(\frac{1}{2} , \frac{\sqrt{3}}{2}\right)$

#### Explanation:

The point on a unit circle with angle $\theta$ is given by:

$\left(\cos \theta , \sin \theta\right)$

This is by the definition of the sine and cosine functions.

Therefore, the point on the unit circle with angle $\frac{\pi}{3}$ is:

$\left(\cos \left(\frac{\pi}{3}\right) , \sin \left(\frac{\pi}{3}\right)\right)$

$= \left(\frac{1}{2} , \frac{\sqrt{3}}{2}\right)$