Question

How do you find the point (x,y) on the unit circle that corresponds to the real number `t=(5pi)/6`?

Answer 1

`(x,y)=(-sqrt(3)/2,-1/2)`

Explanation:

I've assumed that "the real number "`t=(5pi)/6` is meant to be the arc length from the positive X-axis.

In this case we have the image below:

The reference angle `pi/6` is one of the standard angles with the ratio of opposite to adjacent sides as indicated above.