# How do you find the point (x,y) on the unit circle that corresponds to the real number t=(5pi)/6?

Dec 30, 2016

$\left(x , y\right) = \left(- \frac{\sqrt{3}}{2} , - \frac{1}{2}\right)$
I've assumed that "the real number "$t = \frac{5 \pi}{6}$ is meant to be the arc length from the positive X-axis.
The reference angle $\frac{\pi}{6}$ is one of the standard angles with the ratio of opposite to adjacent sides as indicated above.