How do you find the point (x,y) on the unit circle that corresponds to the real number #t=(4pi)/3#?

1 Answer

Answer:

Point #(x,y)# on unit circle corresponding to #(4pi)/3# is #(-1/2,-sqrt3/2)#

Explanation:

Just remember that coordinates on the unit circle can be derived using:

(x, y) = (cos A, sin A), where A is the measurement of the angle.

In this case, #A = (4pi)/3#. Now, you can plug in A into (cos A, sin A) to find the x and y coordinates of the answer. Just make sure to set your calculator to radians, since #(4pi)/3# is in radians.

Using this point #(x,y)# on unit circle corresponding to #(4pi)/3# is #(cos((4pi)/3),sin((4pi)/3))# i.e. #(-1/2,-sqrt3/2)#

I hope that helps!